Перегляд вихідного коду сторінки Windows-service-python

[http://code.activestate.com/recipes/576451-how-to-create-a-windows-service-in-python/]  '''how to create a windows service in python (Python recipe) '''

 '''
 Author: Alex Baker
 Date: 7th July 2008
 Description : Simple python program to generate wrap as a service based on example on the web, see link below.
 
 http://essiene.blogspot.com/2005/04/python-windows-services.html
 
 Usage : python aservice.py install
 Usage : python aservice.py start
 Usage : python aservice.py stop
 Usage : python aservice.py remove
 
 C:\>python aservice.py  --username <username> --password <PASSWORD> --startup auto install
 
 '''
 import win32service
 import win32serviceutil
 import win32api
 import win32con
 import win32event
 import win32evtlogutil
 import os
 
 class aservice(win32serviceutil.ServiceFramework):
 
    _svc_name_ = "aservice"
    _svc_display_name_ = "a service - it does nothing"
    _svc_description_ = "Tests Python service framework by receiving and echoing messages over a named pipe"
 
    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)           
 
    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)                    
         
    def SvcDoRun(self):
        import servicemanager      
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,servicemanager.PYS_SERVICE_STARTED,(self._svc_name_, '')) 
        self.timeout = 3000
 
    while 1:
        # Wait for service stop signal, if I timeout, loop again
        rc = win32event.WaitForSingleObject(self.hWaitStop, self.timeout)
        # Check to see if self.hWaitStop happened
        if rc == win32event.WAIT_OBJECT_0:
            # Stop signal encountered
            servicemanager.LogInfoMsg("aservice - STOPPED")
            break
        else:
            servicemanager.LogInfoMsg("aservice - is alive and well")   
 
 
 def ctrlHandler(ctrlType):
     return True
                  
 if __name__ == '__main__':   
     win32api.SetConsoleCtrlHandler(ctrlHandler, True)   
     win32serviceutil.HandleCommandLine(aservice)